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 PHP Code: Calendar for any month any year Jump to:  
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Snippet Name: Calendar for any month any year

Description: Simple, nice looking calendar displays any month and year.

Also see:
» Convert UK Dates To mySQL Format Dates
» Delete files older than 'X'
» String to Date
» Month, Day, Year dropdown boxes
» Calculate date of Easter Sunday
» Define a schedule of holidays
» Add and Subtract dates
» Basic PHP Calendar
» Convert 12 to 24 hour time and vice ve...
» What Season Is It?
» Delete by date
» Days in month #2
» Days in month #1
» Count days between dates
» Find days between dates #1
» Build Date Select Boxes

Comment: (none)

Language: PHP
Highlight Mode: PHP
Last Modified: March 16th, 2009

<?PHP 
 
    # ***  Set time stamp.Check for month requested(value from request form) 
    # ***  If no value has been set then make it for current month 
 
   IF(!$year){$year=2000; } 
     IF(!$req_month || $req_month=="none") 
      { 
         $dt_and_tm=TIME(); 
      } 
      ELSE 
      { 
         $dt_and_tm=MKTIME(0,0,0,$req_month,1,$year); 
      } 
   # *** Find out the month number from the time stamp we just created   
    # *** Find out the day of the week from the same(0 to 6 for Sunday to   
    # *** Saturday) add "1" so that it becomes 1 to 7  
 
         $month=DATE("n",$dt_and_tm); 
         $week_day=DATE("w",$dt_and_tm)+1;      
 
    # *** Set number days in requested month   
 
IF($month==1 || $month==3 || $month==5 || $month==7 || $month==8 || $month==10 || 
$month==12) 
{     
   $no_of_days=31;     
} 
ELSEIF($month==4 || $month==6 || $month==9 || $month==11) 
{   
   $no_of_days=30; 
}   
 
 # *** If the month requested is Feb. Check whether it is Leap Year      
 
ELSEIF($month==2) 
{   
                   IF(DATE("L",$dt_and_tm)) 
                   { $no_of_days=29 ;} 
                   ELSE 
                   {$no_of_days=28;} 
} 
   $month_full=DATE("F",$dt_and_tm); 
 
 
# ************ HTML code goes from here  
# ************ First row in HTML table displays month and year   
# ************ Second row is allotted for week days 
# ************ Table contains six more rows (total 42 table cells)   
?> 
<html> 
<body> 
<table width=300> 
<tr bgcolor="#003366"><td colspan=7> 
<font face="Arial , Times New Roman " size=2 color="#ffffff"><b><?PHP ECHO "$month_full   
$year" ; ?></b></font></td></tr> 
<tr bgcolor="#006699"> 
<td><font face="Arial , Times New Roman " size=2 color="#ffffff">Sun</fon></td><td><font 
face="Arial , Times New Roman " size=2 color="#ffffff">Mon</font></td><td><font 
face="Arial , Times New Roman " size=2 color="#ffffff">Tue</font></td><td><font 
face="Arial , Times New Roman " size=2 color="#ffffff">Wed</font></td><td><font 
face="Arial , Times New Roman " size=2 color="#ffffff">Thu</font></td><td><font 
face="Arial , Times New Roman " size=2 color="#ffffff">Fri</font></td><td><font face="Arial , 
Times New Roman " size=2 color="#ffffff">Sat</font></td> 
</tr> 
<tr bgcolor="silver"> 
<?PHP 
 
# *** We need to start form week day and print total number of days  
# *** in this month.For that we need to find out the last cell.  
# *** While looping end current row and start new row for each 7 cells 
 
$last_cell=$week_day+$no_of_days;       
FOR($i=1;$i<=42;$i++) 
{ 
   IF($i==$week_day){$day=1;} 
   IF($i<$week_day || $i>=$last_cell) 
   { 
 
     ECHO "<td>?</td>"; 
      IF($i%7==0){ECHO "</tr><tr bgcolor=\"silver\">\n";}    
   } 
   ELSE 
   { 
 
        ECHO "<td>$day</td>"; 
        $day++; 
       IF($i%7==0) { ECHO "</tr><tr bgcolor=\"silver\">\n"; } 
 
   } 
} 
?> 
</table></body></html>
 


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